An electric refrigerator rated as 750W operates 8 hours per day. What is the cost of the energy to operate it for the month of June at Rs 2.50 per keh?
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Here is ur answer buddy
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no of units consumed in a day = 750*8 =6000Wh = 6kWh
no of units consumed in 30days = 30*6 =180 units
cost of energy consumption= 180*2.5 = 450Rs
no of units consumed in 30days = 30*6 =180 units
cost of energy consumption= 180*2.5 = 450Rs
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