Question

An electric room heater has a resistance of 25 Ώ and operates at 220 V for 12 minutes.
Calculate heat energy dissipated by it in kilojoules.

Answer 1

Power=v^2/R

220*220/25

=1936watt

1936=heat dissapiated/time in sec

1936=H/12*60

H=1936*12*60=13,93,920J

=1393.920KJ