An electric toaster rated 220V;2.2kWh, works for 2 hours. Find the energy consumed and current drawn. Give the rating of the fuse required for proper working of the appliance.
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In any electrical appliance their is a simple relationship between the power output of a component, the potential difference across that component, and the current running through it. This is because charge times potential difference is energy, so (charge per unit time) times (potential difference) gives (energy per unit time). Thus, we have P=VI.
Substituting I=V/R from ohm's law, the power relationship can be rewritten as P=
R
V
2
. From this formula, the resistance can be calculated as follows.
P=
R
V
2
that is, R=
P
V
2
. The power and voltage are given as100W and 220V.
Therefore, R=
100
220
2
=
100
48400
=484Ω.
Hence, the resistance of the bulb is 484 Ω.
Explanation:
MARK BRAINLIEST
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