Question

an electric train is running at 90 kilometre per hour and by stopping Electric Supply to the engine the train moving with a constant negative acceleration comes to a halt in 20 seconds calculate the acceleration of the train and the distance covered by the train during this time

Answer 1

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Answer 2

Hiya!!!

Here's your answer

U= 90 km/h= 90*5/18
= 2.5 m/s
V=0
T= 20 seconds
Using, v= u+at
0= 2.5+20a
20a= -2.5
a= -2.5/20
a= 0.10m/s
Using, s= ut+1/2at^2
s= 2.5*20+1/2*0.10*20^2
s=10m

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