Question

An electrical appliance having a resistance of 200ohm is operated at 200V. Calculate the energy consumed by the appliance in 5 mins (1) in joule (2) in kWh.

Answer 1

R=200 ohm

V=200v

power =V2/R

=200*200/200

=200watt

energy =power *time

=200*5*60

=60,000joule

in kilowatt-hour ---->

=60,000/1000

=60KWh

Answer 2

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