Question

An electrical appliance is rated 200V-100W. What is the resistance of the appliance ? Five such appliances run simultaneously for 4 hours. What is the energy consumed. Calculate the cost of running these appliances if the per unit cost is Rs 4.60.

Answer 1

by p = v^2/r

r = 400 ohm

cost of running one applaince

= Rs.4.6 X 0.1kW X 4h

= Rs. 1.84

cost of running five appliances

= 1.84 X 5

= Rs. 9.20