An electrical appliance of power 2kw works at potential difference of 220v. does it require fuse of 5A give reason? and complete the questions in picture plz
Answers
Answered by
104
The power of the electrical appliance = 2kw (when changed to watts it shall be 2000w)
The potential difference= 220v
Since, I=P/V, we will observe
2000/220= 9.09v
Thus, the electrical appliance requires a fuse of more than 5A else, with 9.09v the electric fuse will melt and the circuit will get broken, as it is drawing more current than its safe limit.
The potential difference= 220v
Since, I=P/V, we will observe
2000/220= 9.09v
Thus, the electrical appliance requires a fuse of more than 5A else, with 9.09v the electric fuse will melt and the circuit will get broken, as it is drawing more current than its safe limit.
Answered by
23
Answer:
yes it requires the fuse
Explanation:
the power of appliance =2kw
the potential difference=220
and
I=p/v
so,
2000/200=9.09
thus the appliance required a fuse of more than 5A else with 9.09v the electric fuse will melt and the circuit will get broken as it is drawing more current than it is safe
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