An electrical appliances os rated 200V-100W. What 8s the resistance of the appliance?Five such appliance run simultaneously for 4 hour. What is the energy consumed? Calculate the cost of running these appliance if the per unit cost is Rs. 4.60?
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Answer. So, resistance = V²/P = (200)²/100 ohms = 400 ohms. In 4 hours, the energy consumed by one appliance = power * time = 100W * 4hr = 400W-hr = 0.4kWh. Now, for five appliances, total energy consumed = 0.4 * 5 kWh = 2 kWh.
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