Question

An electrical component with a resistance of 50 ohm draws an electric current of 4 A in an electric circuit for 10 minutes. Calculate the heat energy dissipated by the electrical component.

Answer 1

Answer:

480 kilo joules

Explanation:

Given :

• Resistance of the electrical component = R = 50 ohms

• Current flowing through the circuit = I = 4 Amperes

• Time the current flows for = 10 minutes = 600 seconds

To find :

• Heat energy dissipated by the electrical component

Heat energy dissipated = I²RT

Heat energy dissipated = 4²×50×600

Heat energy dissipated = 16×50×600

Heat energy dissipated = 800×600

Heat energy dissipated = 4,80,000 joules

1000 joules = 1 kilo joule

Heat energy dissipated = 480 kilo joules

The heat energy dissipated in the electrical component is equal to 480 kilo joules

Answer 2

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An electrical component with a resistance of 50 ohm draws an electric current of 4 A in an electric circuit for 10 minutes. Calculate the heat energy dissipated by the electrical component.

$\huge{\underline{\red{AnswEr}}}$

GIVEN:

⭐ Resistance(R) of electrical components is 50 Ω.

⭐electric current (I) of components is 4A.

⭐Time taken (T)=10 min

therefore,

10 min convert into second

so, we know that

1 minutes=60 second

10 minutes=(10×60)=600 second

Dissipated of heat energy=I²RT

=4²×50×600

=16×50×600

=800×600

=4,80,000 Joules.

therefore,

the heat energy dissipated by the electrical component is 480 kilo joules