Question

an electrical device of 500w is use daily in a household for 10 hours. Calculate the energy consumed in the month of april.
Answer if you know.​

Answer 1

Answer:

given ,( time taken per day ) t = 10 hrs.

( power ) P = 500 w

( energy ) E = ?

P = \frac{E}{t}P=

t

E

P * T = E

500 * 10 = 5000 w

energy use in 1day = 5000 * 3600 * 10 = 18000 kj

energy used in month of april ( 30 days ) = 18000 * 30 = 540000 kj

Answer 2

Answer:

Given:

t = 10 hrs.

P = 500 w

E = ?

P = E/T

P × T = E

500 ×10 = 5000 w

Energy use in 1day

= 5000 ×3600 ×10 = 18000 kj Energy used in month of april ( 30 days )

= 18000 × 30 = 540000 kj

=5.4×10^5kJ