An electrical iron consumes energy at rate of 420W when heating is at maximum rate and 180W when heating is at minimum.The voltage is 220V. What is the current and resistence in each case.
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P = VI
(1 ) 420 ÷ 220 = I
(2) 180 ÷ 220 = I
p = V × V ÷ R
(1) 420 = 220 × 220 ÷ R
(2) 180=220 × 220 ÷ R
(1 ) 420 ÷ 220 = I
(2) 180 ÷ 220 = I
p = V × V ÷ R
(1) 420 = 220 × 220 ÷ R
(2) 180=220 × 220 ÷ R
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