Question

An electrical iron uses a power of 1200 W .If operated at 220V for 2 hours daily find out current flowing through iron , it's resistance and number of units cossumed in the month of January​

Answer 1

Answer:5.4545A, 40.333.Ohm, 72KWH/month

Step-by-step explanation:

Here P=1200W

Voltage (V)=220V

Time(T)=2 hrs / day

Now we know, P=V × I

Or, I=P/V=1200/220=120/22=5.4545 Ampere

Again, To find Resistance (R)

P=V^2/R

Or, R=V^2/P=(220×220)/1200=48400/1200=40.333 Ohm

Now power consumed in 1 day =(1200/1000)Kilowatts ×2 hours=2.4 KWH/day

Therefore in one month, (2.4×30)=72 KWH/month