Question

An electrician puts a fuse of rating 5A in that part of domestic electric circuit in which an electrical heater of rating 1.5 KW, 220 V is operating. What is likely to happen in this case and Why? what change , if any needs to be made?

Answer 1

Hii friend,

The fuse will melt and the circuit breaks if electric current more than the rating o fuse flows in the circuit. Electric current following in the circuit,

I = P/V = 1.5 × 1000W/220V = 6.82 A.

Since,

Current flowing in the circuit which is 6.82 A is more than the rating of fuse which is 5A , therefore , the fuse will melt and the electrical heater doesn't work. To operate the heater, fuse of rating 10A is to be put in the circuit.


HOPE U GOT IT.... :-)

Answer 2

hi mate

here is your answer

If the electric current will be more than the rating of fuse, then the fuse will melt. So, the electric current in this case is,

$I = \frac{P}{V}$

$I = \frac{1.5 \: KW}{220 \: V}$

$I = \frac{1.5 \times 1000 \: W}{220 \: V}$

$I = 6.82 \: A$

Since current flowing in circuit (6.82A) is more than the rating of fuse (5A), the fuse will melt and the electric heater doesn't work.

To operate this, the fuse of rating 10A should be used.

hope it helped

keep smiling :-)