Question

An electrician requires a capacitance of 6u F in a circult across a potential difference of 1.5 KV. A large number of 2uf capacitors which can withstand a potential difference of not more than soovare able the minimum number of capacitors required for the purpose is (C) 6 (D) 27 (A) 3 (B) 9​

Answer 1

Explanation:

Given An electrician requires a capacitance of 6u F in a circuit across a potential difference of 1.5 KV. A large number of 2uf capacitors which can withstand a potential difference of not more than 500 V. The minimum number of capacitors required for the purpose is

• So total required capacitance will be
• C = 6 µF
• Potential difference V = 1.5 KV = 1500 V
• So each capacitance C1 = 2 µ F
• So the potential difference that withstands each capacitor is V1 = 500 V
• Number of capacitors in each row = 1500 / 500
•                                                       = 3
• So there are 3 capacitors in each row
• Therefore Capacitance of each row = 1/2 + 2 + 2
•                                                         = 1/6 µF
• Now equivalent capacitance = 1/6 + 1/6 +--------------- n terms
•     So we get n/6
•     So n/6 = 6
•     Or n = 36
• So we need 36 rows for 3 capacitors
• Now minimum will be 36 x 3 = 108
• So 108 capacitors are required.

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https://brainly.in/question/4646994