Question

an electrochemical cell is made of Nickel and copper electrodes with their standard reduction potential is 0.25 vV and plus 0.34 V respectively slide the anode and cathode ray send the cell and find E.M.F of the cell​

Answer 1

Answer:I think you should write who is anod and cathod. I gave equation below. With the help of it you can calculate.

Explanation:EMF=E°red(cathod) - E°red(anod).

Answer 2

E°cell = 0.59 v

•

Cu²⁺ + 2e- ------> Cu E° = 0.34v

Ni²⁺ +2e- --------> Ni E° = -0.25v

•It is clear that Cu²⁺ will get reduce

& Ni²⁺ will get oxidize

•Now , cell reaction will be

Cu²⁺ + 2e- ------> Cu

Ni -----------> Ni²⁺ +2e-

•Cu²⁺ + Ni --------> Cu + Ni²⁺

•E°cell = E°c -E°a ( when reduction

potential is considered )

•E°cell = 0.34 -(-0.25)

•E°cell = 0.59 v