Chemistry, asked by aryanam4001, 1 year ago

an electrolyte AB is 50% ionised in aqueous solution. Calculate the freezing point of 1 molal aqueous solution

Answers

Answered by kobenhavn
28

Answer: The freezing point of the solution is 270.21.

Explanation:

\Delta T_f=i\times K_f\times m

\Delta T_f = depression in freezing point

i= Van'T Hoff factor

K_f = freezing point constant = 1.86 K kg/mol

m = molality = 1

AB\rightarrow A^+B^-

\alpha =\frac{i-1}{n-1}

\alpha= degree of dissociation

n = number of ions on complete dissociation

50\%=0.5=\frac{i-1}{2-1}

i = 1.5

\Delta T_f=1.5\times 1.86 K kg/mol\times 1

\Delta T_f=T^{o}_f-T_f=273 K-T_f

273 K-T_f=1.5\times 1.86\times 1

T_f=270.21K

The freezing point of the solution is 270.21K.

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