Question

an electromagnetic radiation point source operates at a 250W power with a 10% efficiency. The average energy density at a point distant 10m from the source is​

Answer 1

Answer:

Intensity of EM wave is given by:-

I=

4πR

2

P

=V

av

.c=

2

1

ε

0

E

0

2

×c

⇒E

0

=

2πR

2

ε

0

c

P

=

2×3.14×(3)

2

×8.85×10

−12

×3×10

8

1500

=73

m

V