Question

An electromagnetic wave going through vacuum is described by
E = E0 sin (kx − ωt); B = B0 sin (kx − ωt).
Then,
(a) E0 k = B0 ω
(b) E0 B0 = ωk
(c) E0 ω = B0 k
(d) None of these

Answer 1

(a) E0 k = B0 ω

The relation between E0  and B0 is given by E0B0=c  ...(1)

Here, c = speed of the electromagnetic wave

The relation between ω (the angular frequency) and k (wave number):

ωk=c   ...(2)

Therefore, from (1) and (2), we get:

E0B0=ωk=c

⇒E0k=B0ω

Answer 2

Answer:

this answer is a.Eok= Bok