An electromagnetic wave, going through vacuum is
described by E = E0 sin(kx -⍵t) . Which of the following
is independent of wavelength ?
(a) k (b) ⍵
(c) k/⍵ (d) k⍵
Answers
Answered by
4
Answer:
C) k / ⍵
Explanation:
The given quantities can be expressed as,
K is given by,
K = 2π / lambda
Then,
w = 2πv
c = v × lambda
w = 2π × C / lambda
K/w is guven by,
K / w = (2π/lambda) / (2πC / lambda) = 1/C
Also,
Kw = 2π/lambda × 2πC /lambda
So, k/w is an independent quantity of wavelength.
Answered by
1
E = E0 sin(kx -⍵t) .
we know that,
k=2π/w
w = wavelength
⍵ =2π f
f represents frequency
we know that ,
f= c/w
⍵ =2π c /w
(a) k = 2π/w
hence ,k depends upon wavelength
(b)⍵ =2π f = 2π c/w
hence , ⍵ depends upon wavelength
(c) k/⍵ = 2π×w/2π×w ×c
k/⍵ =1 /c
k/⍵ doesn't depend upon wavelength✓
(d) k⍵ = 4π²c/w²
k⍵ depends upon wavelength
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