Physics, asked by ambrishverma, 9 months ago

an electromagnetic wave having wavelengths 5000A will lie in which region of electromagnetic spectrum​

Answers

Answered by Rajguru11
3

Answer:

The electromagnetic spectrum is the distribution of electromagnetic radiation according to energy (or equivalently, by virtue of the relations in the previous section, according to frequency or wavelength).

Regions of the Electromagnetic Spectrum

The following table gives approximate wavelengths, frequencies, and energies for selected regions of the electromagnetic spectrum.

Spectrum of Electromagnetic Radiation

Region Wavelength

(Angstroms) Wavelength

(centimeters) Frequency

(Hz) Energy

(eV)

Radio > 109 > 10 < 3 x 109 < 10-5

Microwave 109 - 106 10 - 0.01 3 x 109 - 3 x 1012 10-5 - 0.01

Infrared 106 - 7000 0.01 - 7 x 10-5 3 x 1012 - 4.3 x 1014 0.01 - 2

Visible 7000 - 4000 7 x 10-5 - 4 x 10-5 4.3 x 1014 - 7.5 x 1014 2 - 3

Ultraviolet 4000 - 10 4 x 10-5 - 10-7 7.5 x 1014 - 3 x 1017 3 - 103

X-Rays 10 - 0.1 10-7 - 10-9 3 x 1017 - 3 x 1019 103 - 105

Gamma Rays < 0.1 < 10-9 > 3 x 1019 > 105

Explanation:

The notation "eV" stands for electron-volts, a common unit of energy measure in atomic physics. A graphical representation of the electromagnetic spectrum.

Answered by handgunmaine
5

It falls on visible region .

To answer this question we should know the wavelength range of E.M waves.

So , the range is :

RAYS                                  WAVELENGTH

Gamma-rays                          <  0.01 Angstrom

X-rays                                     1 nm - 1 pm

Ultraviolet                              400 nm - 1 nm

Visible                                    750 nm - 400 nm

Near-infrared                         2.5 μm - 750 nm

Infrared                                  25 μm - 2.5 μm

Microwaves                           1 mm - 25 μm

Radio Waves                          > 1 mm

Now , wavelength of given E.M waves is 5000 A = 500 nm .

From the above table we can see it falls on Visible spectrum .

Hence , this is the required solution .

Learn More :

E.M Waves

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