Question

An electromagnetic wave is propagating along x direction, the magnetic field oscillating at a frequency 5×10 8HZ and has an amplitude 10 -7T , acting along the y direction. (a) what is the wavelength of the wave? (b) write the expression representing the corresponding oscillating electric field.

Answer 1

Explanation:

(a) frequency*wavelength=speed of electromagnetic wave

$wavelngth = 3 \times {10}^{8} \div (5 \times {10}^{8} )$

•°•,

$wavelength = \frac{3}{5} = 0.6m$

(b)

$\frac{e}{b} = c$

$e = b \times c$

•°•,

$e = {10}^{ - 7} \times (3 \times {10}^{8} ) = 30$

amplitude of electric field(e) = 30V/m

w=2π*frequency = π×10^9 rad/s

k=2π/wavelength = 10π/3 m^-1

E=e[sin(wt-kx)]

E=30 [sin(π×10^9t - 10π/3x)] V/m

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