Question

An electromagnetic wave of intensity 30 W/m² is incident on a surface of area 2 m². If the surface is perfectly absorbing, then the amount of momentum transferred to the surface in 10 s will be


2x 10-6 kg m/s

2 x 10⁰ kg m/s

4 x 10-⁹ kg m/s

10-8 kg m/s​

Answer 1

Answer:

2 × 10 to the power -6bis correct answer I hope

Answer 2

2 × 10⁻⁶ kg m/s

Momentum transferred =

Momentum transferred = energy transferred / speed of light

Here , Intensity = 30 W/m²

area = 2 m²

speed of light = 3 × 10⁸ m/s

Momentum transferred = 30 × 2 / 3 × 10⁸

= 2 × 10⁻⁷

Momentum transferred in 10s = 2 × 10⁻⁷ × 10

= 2 × 10⁻⁶ kg m/s

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