An electron above the earth is balanced by the gravitational force and the electric field of the earth. Find the electric field of the earth.
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Answered by
18
Answer:
E=9.1×10×(-31)×9.8/1.6×10×(-19)
or
E= 568×10×(-11 ) N/C
Explanation:
Under equilibrium condition
electric force due to the earth acting upwards=gravitational force acting downwards
so,
qE = mg
or
E = mg/q
here,
q=e=1.6×10-19 c
m=9.1×10-31 kg
g=9.8m/s²
so
E= 9.1×10×(-31)×9.8/1.6×10×(-19)
or
E = 5.68× 10 to the power (-11) N/C
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