An electron accelerated by a potential difference of
300 V, is moving at a distance of 4 mm from a long,
straight wire. If a current of 5 A flows through the
wire, what will be the force acting on the electron?
Answers
Answer:
Explanation:
The energy the electron has gained is E=qV (coulombs and volts).
Work out the speed of the electron using energy = 1/2 mv^2 (mass mass of electron and v is speed) You will need to use the speed v later.
Work out the magnetic flux density at a distance r (4 x10^-3 m) from the wire carrying a current of 5A using
Finally you will have to assume that the electron is moving perpendiculary to the magenic field (parallel to the wire).
Force on a moving charged particle F=BqV
You want F, B is from the line above abd v is the speed from the earlier calculation. The direction you can find from the left hand motor rule. (not forgetting that the current is flowing =in the opposite direction to the electrons velocity)
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