An electron after being accerlated through a potential difference of 100 v enters a uniform magnetic field of 0.004T perpendicular to its direction of motion. Calcuate the radius of the path described by electron
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Keeping in view that, an electron after being accelerated through a potential difference of 100 v enters a uniform magnetic field of 0.004 t perpendicular to its direction of motion. The radius of the electron would be; 8.43×10⁻³m. Explanation: r= 1/B√2mV/e
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