Question

An electron and a proton are at a distance of 0.53 angstrom find their dipole moment

Answer 1

The formula for dipole moment is   μ= charge  X distance

charge on electron = charge on proton = 1.6 x 10^-19

distance = 0.53 A° ..........i:e 0.53 X 10^-10

dipole moment= (1.6*10^-19)(0.53*10^-10)

                         = 0.848* 10^-29

Answer 2

The dipole moment of an electron and a proton is $1.69\times 10^{-29}\ C-m$.

Explanation:

It is given that,

Distance between an electron and a proton is 0.53 Angstrom

$1\ A=10^{-10}\ m$

We know that the product of charge and distance between charges is called dipole moment. It is given by :

$D=q\times 2l$

Charge on electron and proton is same

$D=1.6\times 10^{-19}\times 2\times 0.53\times 10^{-10}$

$D=1.69\times 10^{-29}\ C-m$

So, the dipole moment of an electron and a proton is $1.69\times 10^{-29}\ C-m$. Hence, this is the required solution.

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