an electron and a proton cross the area of cross section of conductor in the opp direction in one second .calculate the amount of charge in the conductor.
Answers
Answer:
Consider a conductor of length of L and cross sectional area A.
When an electric field E is applied across it, the electrons are drifted opposite to the applied field.
Volume of a conductor =LA=1 in this case.
Let n be the number of free electrons per unit volume of conductor.
Total charge on all the electrons in the conductor =nLAe
where, e is the charge of each electron.
⇒q=nLAe=neAL
But current, I=
t
q
=
t
neAL
=
t
ne
asAL=1
Explanation:
Consider a conductor of length of L and cross sectional area A.
When an electric field E is applied across it, the electrons are drifted opposite to the applied field.
Volume of a conductor =LA=1 in this case.
Let n be the number of free electrons per unit volume of conductor.
Total charge on all the electrons in the conductor =nLAe
where, e is the charge of each electron.
⇒q=nLAe=neAL
But current, I=
t
q
=
t
neAL
=
t
ne
asAL=1
Answer:
Consider a conductor of length of L and cross sectional area A.
When an electric field E is applied across it, the electrons are drifted opposite to the applied field.
Volume of a conductor =LA=1 in this case.
Let n be the number of free electrons per unit volume of conductor.
Total charge on all the electrons in the conductor =nLAe
where, e is the charge of each electron.
⇒q=nLAe=neAL
But current, I=
t
q
=
t
neAL
=
t
ne
asAL=1
Explanation:
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