An electron and a proton , having equal moment , enter a mag. field at an angle 90° with field lines. What will be the ratio of their trajectories?
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Momentum of both electron and proton are equal. - (Given)
Then , P = mv is (constant).
We know that,
F = q v B sin θ.
(Here , F - force, q - charge, v - velocity, B - magnetic field)
This force provides the required centripetal force for the motion along circular path whose radius is r.
Centripetal force = mv^2/r
Then,
Mv^2/r=qvb sin θ
Here, θ = 90 degrees .
Then,
R = mv/bq
= 1:1
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