An electron and a proton, having equal momenta, enter a uniform magnetic field at right angles to the field lines. What will be the ratio of their trajectories? (
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Momentum of both electron and proton are equal. - (Given)
Then , P = mv is (constant).
We know that,
F = q v B sin θ.
(Here , F - force, q - charge, v - velocity, B - magnetic field)
This force provides the required centripetal force for the motion along circular path whose radius is r.
Centripetal force = [math]\frac{mv^2}{r}[/math]
Then,
[math]\frac{mv^2}{r} = qvB sin\theta [/math]
Here, θ = 90 degrees .
Then,
[math]r= \frac{mv}{Bq}= 1 : 1[/math]
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