Question

An electron and proton move with same speed in uniform magnetic field of equal magnitude compare radii of circular path​

Answer 1

Answer:

mv²/R=Bqv( centripetal force= force of magnetic field)

or R=mv/Bq

A proton enters a uniform magnetic field with a path perpendicular to the field lines and moves in a circular path of radius R. An electron enters the same magnetic field at the same speed in a path perpendicular to the field.

Compared to the protons path, the radius of the electrons circular path is A smaller radius. since the mass of electron is less.