An electron beam can undergo diffraction by crystals. Though what potential should a beam of electrons be accelerated so that its wavelenght becomes equal to 1.54 Angestrom
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ANSWER
For an electron
2
1
mu
2
=eV; also λ=
mu
h
∴
2
1
m
m
2
λ
2
h
2
=eV
V=
2
1
mλ
2
e
h
2
V=
2×9.108×10
−31
×(1.54×10
−10
)
2
×1.602×10
−19
1×(6.626×10
−34
)
2
=63.44 volt
BRAINALIST
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