An electron beam can undergo diffraction by crystals. Through what potential should a beam of electrons be accelerated so that its wavelength is equal to 1.6 A? (1)58.90 V (2)85.75 V (3)45.35 V (4)105.31 V
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Answered by
5
Answer:
wavelength= h/√2meV
substitute the values n get d ans
h= 6.6×10^-34 J.s
e=1.6×10^-19 c
m= 9.1×10^-31 kg
Answered by
0
Answer:
opt a} 58.9V
Explanation:
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