Question

An electron beam is accelerated by a potential difference of 10000 volts. What is the wavelength of the wave associated with the electron beam ? Mass of electron = 9.11 1031 kg.

Answer 1

Hello Dear,

◆ Answer -

λ = 1228 A°

● Explaination -

# Given -

m = 9.11×10^-31 kg

V = 10 kV = 10^4

# Solution -

de Broglie wavelength of the particle is calculated as -

λ = h / √(2meV)

λ = 6.63×10^-34 / √(2 × 9.11×10^-31 × 1.6×10^-19 × 10^4)

λ = 1.228×10^-13 m

λ = 1228 A°

Therefore, de Broglie's wavelength of electron is 1228 A°.

Hope this helps you...