Question

An electron beam of 1.67 X 1021 electrons is passed between two ends of conductor in 20s. Calculate the charge.​

Answer 1

Explanation:

charge = No. of electrons × charge of electron

$q \: = \: n \: e$

$q \: = 1.67 \times {10}^{21} \times 1.67 \times {10}^{ - 19}$

$q \: = 2788.89 \: coulomb$