Question

An electron entering field normally with a velocity 4*10^7m/s travels a distance of 0.10m in an electric field of intensity 3200V/m. What is deviation from its path? ​

Answer 1

In y direcn.

y = 0.5*(eE/m)*t^2

put the value of charge mass and given electric field inensity

and get the reln. in y and t.

Calculate t from:

x = v*t

0.10 = 4*10^7*t

and put it in y eqn. and the deviation value .i.e. y.

Answer 2

Answer:

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