An electron enters a uniform magnetic field B = Boſ with its initial velocity v = 8 x 104 i m/s. Direction of magnetic force experienced by the electron is (a) along positive z-axis (b) along x-axis (c) along y-axis (d) along negative z-axis
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Given:
Magnetic field: Bo j
Velocity= 8 x 104 i m/s
To find:
Direction of magnetic force
Solution:
A moving charge in a magnetic field experiences a force such that velocity, the direction of the magnetic field and the force experienced by the electron are all mutually perpendicular to each other.
The direction of force is given by F= q(VXB)
Direction of VXB = i X j = k
But since the charge on an electron is negative, direction of force is -k
Hence, Direction of magnetic force experienced by the electron is (d) along negative z-axis
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