An electron enters normally in an uniform electric field of intensity 3200V/m with speed of 4×10^7m/s.the electron covers a distance of 0.10 m .what is the deflection of the electron?
JinKazama1:
1.76 * 10^-3 m?
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Final Answer : 1.76mm
Understanding :
1) Distance = speed * time
Find time from here.
By Calculation, it came out
t = 0.25 * 10^(-8)s
2) acceleration of electron = e E / m
in direction of Electric Field.
Use Newtons equations to get
Substitute the value of time in
deflection = 1/2 * a * t.^2
deflection = 1.76 mm
For Calculation see pic.
Understanding :
1) Distance = speed * time
Find time from here.
By Calculation, it came out
t = 0.25 * 10^(-8)s
2) acceleration of electron = e E / m
in direction of Electric Field.
Use Newtons equations to get
Substitute the value of time in
deflection = 1/2 * a * t.^2
deflection = 1.76 mm
For Calculation see pic.
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