Question

An electron experiences a force of 8 x 10-14 N towards east in a uniform electric field. Then, the electric field in which the electron is moving is
(A)
5 × 10-NC-1 towards east
(B) 5 x 105 NC-1 towards west
(C) 5 x 10-5 NC-1 towards east
(D) 5 x 10-5 NC-1 towards west​

Answer 1

The electric field in which the electron is moving is 5 × 10⁵ NC⁻¹ towards East direction

Therefore, option (C) is correct.

Explanation:

Given:

The force on electron

$F=8\times 10^{-14}$ N in East direction

To find out:

The electric field

Solution:

We know that if E is electric field, then the force acting on charge q is given by

$F=qE$

Clearly the direction of Electric field will also be the direction of the Force as charge is a scalar quantity

We know that charge in electron

$q=1.6\times 10^{-19}$ C

Therefore, the Electric Field is

$E=\frac{F}{q}$

$\implies E=\frac{8\times 10^{-14}}{1.6\times 10^{-19}}$

$\implies E=5\times 10^5$ N/C

The direction will be towards East

Hope this answer is helpful.

Know More:

Q: find the electric intensity at a point with a charge of 5 into 10 ki power minus 4 coulomb experience a force of 2.25 Newton.

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