An electron has a circular path of radius 0.01m in a perpendicular magnetic induction 10^-3T. Find the speed of the electron
Options:-
A)1.76 x 10^6 m/s
B)1.76 x 10^-6 m/s
C)1.76 m/s
D)none
Answers
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Bqv = mv² / r
v = Bqr / m
= (10⁻³ T × 1.6 × 10⁻¹⁹ C × 0.01 m) / (9.1 × 10⁻³¹ kg)
= 1.76 × 10⁶ m/s
Speed of electron is 1.76 × 10⁶ m/s
(A) is the correct option.
v = Bqr / m
= (10⁻³ T × 1.6 × 10⁻¹⁹ C × 0.01 m) / (9.1 × 10⁻³¹ kg)
= 1.76 × 10⁶ m/s
Speed of electron is 1.76 × 10⁶ m/s
(A) is the correct option.
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