Question

An electron has a speed of 500m/sec with uncertainty of 0.2%. What is the uncertainty in locating its position

Answer 1

Answer:

Speed of the electron = v = 500 m/s.

uncertainty in speed is 0.02%

Δv=0.005%of500 m/s

=0.005/100×500=0.025 m/s

According to Heisenberg uncertainty principle,  

Δx.Δp>=h/4π where Δx= uncertainity in position

 mΔv​=9.1×10  −31 ​×0.025 m/s = 2.27\times10^{-32}kg​m/s​

Δx.Δp>=h/4π

Δx>=h/4πΔp

 Δx>=6.63×10  −34

/4×3.14×2.27×10  −32

  =2.32×10  

−3   m