An electron has a spewd of 500m/s
with uncertainty of 0.02%. What is the uncertainty in locating its position?
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Answer:
Explanation:
We know from Heisenberg's theory of uncertainty that
X.P is greater than or equal to h/4π ( h = 6.6 × 10^-34 JS)
Given V/V = 0.02
V= 2/100× 500 = 10 m/s.
Now the values can be put in the equation above mentioned.
NOTE:- P= MV
M(mass of electron) = 9.31 × 10^-31 kg
V= 10 m/s
P= 93.1 × 10^-31 kgm/s
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