Question

an electron has a velocity of 5×10^-7ms accurate upto 0.002% calculate the uncertainty in its position(m=9.1×10^-31kg,h=6.62×10^-34)


ans is:5.79 ×10^-7 need explanation
class 11th chemisrty​

Answer 1

Answer:

Δx=0.0144 m

Explanation:

From Heisenberg uncertainty principle,

Δx×Δp=  

4π

h

​  

 

Δx=  

4π×mΔv

h

​  

 

where,  

Δv=40×0.0001

m=9.1×10  

−

31 Kg

h=6.63×10  

−34

 J.sec

Δx=0.0144 m