Question

An electron has speed 500m/s correct up to 0.01/ with minimum accuracy. Can you locate the position of this electron?

Answer 1

Explanation:

Speed of the electron = v = 500 m/s.

uncertainty in speed is 0.02%

Δv=0.005%of500 m/s

=0.005/100×500=0.025 m/s

According to Heisenberg uncertainty principle,

Δx.Δp>=h/4π where Δx= uncertainity in position

mΔv=9.1×10

−31

×0.025 m/s = 2.27\times10^{-32}kgm/s

Δx.Δp>=h/4π

Δx>=h/4πΔp

Δx>=6.63×10

−34

/4×3.14×2.27×10

−32

=2.32×10

−3m