Question

an electron having 450 EV of energy moves at right angle to a uniform magnetic field of flux density 1.50 ×10^-3T . Find the radius of its circular orbits. ( Given specific charge of the electron 1.76×10^+11ckg.
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Answer 1

Answer:

we can have12mv2=500 eVv=2×500×1.6×10−19J9.1×10−31kg−−−−−−−−−−−−√=13.26×106 m/sAgain Lorentz magnetic force supplies centripetal force evB=mv2rr=mveB=(13.26×106)1.76×1011×20×10−3=0.376×10−2 mr=0.376 cm