Question

An electron having 450 eV of energy moves at right angle to a uniform magnetic flux density of 1.50 x 10-3 Tesla.. Calculate the velocity and radius of the circular orbit due to electron. Use specific charge of electron = 1.76 × 10¹1 c/kg.​

Answer 1

E=

2

1

mv

2

⇒v=

m

2E

r=

Be

mv

=

Be

m

m

2E

=

Be

2mE

r=

1.6×10

−19

×0.4

2×1800×1.6×10

−19

×9.1×10

−31

=3.58×10

−4

m

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