Question

An electron having an initial velocity of 10 exp+3 cms-1 is directed from a distance of 1 mm at another electron whose position is fixed how close to the stationary electron will the other approach

Answer 1

Answer:

Initial velocity of the electron is u =5×10

4

m/s

Acceleration of the electron is a=10

4

m/s

2

From first equation of motion,

v=u+at

2u=u+at

t=u/a=(5×10

4

)/(10

4

)=5s

(C) 5

Answer 2

Concept introduction:

The direction of a body or object's movement is defined by its velocity. In its basic form, speed is a scalar number. In essence, velocity is a vector quantity. It is the speed at which distance changes. It is the displacement change rate.

Explanation:

We have to tell whose position is fixed how close to the stationary electron will the other approach.

An electron having an initial velocity of $10$ $exp$$+3$ $cms^{-1}$ is directed from a distance of $1 mm$ at another electron.

initial velocity of the electron is $u =5*10 m/s$

Acceleration of the electron is $a=10 m/s^2$

From first equation of motion,

$v=u+at$

$2u=u+at$

$t=u/a=(5*10)/10$

$= 5$

Final answer:

The final answer of the question is $5s$

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