Question

An electron having kinetic energy of 1840 eV and a proton having a KE of leV follow circular paths of radii 9.11 cm and R respectively in a uniform magnetic field. Then Ris (a) 9.11 cm (b) 9.1172 cm (c) 18.22 cm 9.11 (d) cm V2
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Answer 1

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An electron of energy 1800 eV describes a circular path in magnetic field of flux density 0.4 T. The radius of path is (q = 1.6 X 10−19 C, me = 9.1 X 10−31 kg)

Explanation:

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Answer 2

An electron of energy 1800 eV describes a circular path in magnetic field of flux density 0.4 T. The radius of path is (q = 1.6 X 10−19 C, me = 9.1 X 10−31 kg)