Question

An electron having mass 'm' and kinetic energy E enter in uniform magnetic field B perpendicularly, then its frequency will be :-

Answer 1

The frequency of revolution of charged particle in a perpendicular magnetic field is

Answer 2

The frequency is $\dfrac{eB}{2\pi m}$

Explanation:

Given that,

Mass of electron = m

Kinetic energy  of electron = E

The frequency of revolution of charged particle in a perpendicular magnetic field

We need to calculate the frequency

Using formula of frequency

$\nu=\dfrac{1}{T}$

$\nu=\dfrac{1}{\dfrac{2\pi r}{v}}$

$\nu=\dfrac{v}{2\pi\times r}$....(I)

We need to calculate the radius

Using electric and magnetic force

$\dfrac{mv^2}{r}=evB$

$r=\dfrac{mv}{eB}$

Put the value of r in the equation (I)

$\nu=\dfrac{v}{2\pi}\times\dfrac{eB}{mv}$

$\nu=\dfrac{eB}{2\pi m}$

Hence, The frequency is $\dfrac{eB}{2\pi m}$

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Topic : magnetic field

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