Question

An electron in 3d-subshell has orbital angular momentum :
??​

Answer 1

Answer:

√6 h/2π

Step-by-step explanation:

For 3d orbital, l = 2; Putting l=2 in the above expression, we get

Orbital angular momentum = √2(2+1) h/2π

                                            = √6 h/2π

Answer 2

Answer:

Step-by-step explanation:

Concept:

The sum of the orbital angular momenta from each electron creates the total orbital angular momentum, which has a magnitude of square root of $\sqrt{} L(L + 1) (L)$ , where L is an integer.

A subatomic particle with a negative charge is called an electron. It can either be free (not attached to any atoms) or bonded to an atom's nucleus. Atomic electrons are organized into spherical shells with different radii to represent different energy levels. The energy held within an electron increases with the size of the spherical shell.

Given:

An electron in $3d$ - Subshell

Find:

To find the orbital angular momentum of an electron in $3d$ - Subshell

Solution:

The orbital angular momentum of an electron in 3d-subshell is

$\sqrt{6h} /2\pi$

The following formula gives the orbital angular momentum for a given subshell with azimuthal quantum number $2$ :

$L = \sqrt{l(l+1)} h/2\pi$

For $3d$orbital,$l = 2$

$L = \sqrt{2(2+1)} h/2\pi$

⇒ $\sqrt{2(3)} h/2\pi$

⇒ $\sqrt{6} h/2\pi$

Hence an electron in $3d$ - Subshell has orbital angular momentum of $\sqrt{6} h/2\pi$.