An electron in a H-atom in its ground state absorb 1.5 times as much energy as the minimum required for its escape (13.6eV) from the atom .what is wavelength of the emitted electron?
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8
Energy absorbed = 1.5 × 13.6 eV = 20.4 eV
E = hc / λ
By substituting values of h and c in above formula
E = 1240 eV.nm / λ
λ = 1240 eV.nm / E
λ = 1240 eV.nm / 20.4 eV
λ = 60.78 nm
Wavelength of emitted electron is approximately 60.78 nm
E = hc / λ
By substituting values of h and c in above formula
E = 1240 eV.nm / λ
λ = 1240 eV.nm / E
λ = 1240 eV.nm / 20.4 eV
λ = 60.78 nm
Wavelength of emitted electron is approximately 60.78 nm
Answered by
5
Explanation:
correct answer is 4.7angstrom
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